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9x^2+45x-18=0
a = 9; b = 45; c = -18;
Δ = b2-4ac
Δ = 452-4·9·(-18)
Δ = 2673
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{2673}=\sqrt{81*33}=\sqrt{81}*\sqrt{33}=9\sqrt{33}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(45)-9\sqrt{33}}{2*9}=\frac{-45-9\sqrt{33}}{18} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(45)+9\sqrt{33}}{2*9}=\frac{-45+9\sqrt{33}}{18} $
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